Answer: the power P is equal to power factor of 0. 8 times current of 3 amps times voltage of 110 volts. AC three phase volts to watts calculation formula. The real power P in watts is equal to square root of 3 times the power factor PF times the phase current I in amps, times the line to line RMS voltage VLL in volts: p voltage times current For a resistor in a DC Circuit the power is given by the product of applied voltage and the electric current: P VI Power Voltage x Current. watts volts x amperes. Enter data in any two of the boxes, then click on the active text for the quantity you wish to calculate.
Aug 29, 2005 The instant power in an electric circuit is [texp(t) v(t). i(t)[tex. This is allways valid. What happens with reactive circuits and sinusoidal voltages and currents is that the peak value of the power is different of the product of the peak values of voltage and current. p voltage times current
Dec 27, 2016 Power is a function of voltage times the volume of electrons (current). Power is the ability to do work and is measured in Watts. The higher the voltage the more power you have with the same current (Watts (power) Volts x Amps. Ohms Law and Power The relationship between Voltage, Current and Resistance in any DC electrical circuit was firstly discovered by the German physicist Georg Ohm. Georg Ohm found that, at a constant temperature, the electrical current flowing through a fixed linear resistance is directly proportional to the voltage applied across it, and also inversely proportional to the resistance. Ohm's Law: Voltage equals Resistance times Current. Given any two, you can figure out the other using simple algebra. p voltage times current Ohms Law How Voltage, Current, and Resistance Relate Chapter 2 Ohm's Law The first, and perhaps most important, the relationship between current, voltage, and resistance is called Ohms Law, discovered by Georg Simon Ohm and published in his 1827 paper, The P(t) is the instantaneous power, measured in watts (joules per second) V(t) is the potential difference (or voltage drop) across the component, measured in volts I(t) is the current through it, measured in amperes. If the component is a resistor with timeinvariant voltage to current ratio, then: How can the answer be improved? The root mean square voltage or current are the DC equivalent voltage and current that will produce the same power dissipation over time. If the average power dissipation is \12\ W, then such a power dissipation can be steadily produced by \\sqrt22\ VDC multiplied by \\sqrt22\ A DC.