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# Transpose of a vector times a vector

##### 2019-12-08 17:04Product of a vector and it's transpose (Projections) Ask Question 7. 7 \begingroup \begingroup @Boris I understand your point that it is not number in case of matrix multiplication, but in the condition of orthogonality aren't we taking dot products?

Matrixvector product. To define multiplication between a matrix A and a vector \vcx (i. e. , the matrixvector product), we need to view the vector as a column transpose of a vector times a vector a' is the transpose of a, which makes a' a row vector, b' is the transpose of b, which makes b' a row vector, and. s is a scalar; that is, s is a real number not a matrix. Note this interesting result. The product of two matrices is usually another matrix. However, the inner product of two vectors is different.

and the transpose of a column vector is a row vector. The set of all row vectors forms a vector space called row space, similarly the set of all column vectors forms a vector space called column space. The dimensions of the row and column spaces equals the number of entries in the row or column vector. transpose of a vector times a vector

Oct 19, 2010 A row vector multiplied by its transpose (column) gives a scalar if I'm right (dot product). I guessed that e times its transpose (ee') in my case is not the usual dot product but the multiplication of a column vector by a row vector. Given a vector X with p rows, then XX' is a pxp matrix. This type of calculation is sometimes useful in multivariate analysis. Syntax: LET VECTOR TIMES TRANSPOSE. where is a vector for which the vector times transpose is to be computed; and where is a Jun 14, 2017  Video transcript. Using this result, the dot product of two matrices or sorry, the dot product of two vectors is equal to the transpose of the first vector as a kind of a matrix. So you can view this as Ax transpose. This is a m by 1, this is m by 1. Now this is now a 1 by m matrix, and now we can multiply 1 by m matrix times transpose of a vector times a vector How can the answer be improved? GLM is based on GLSL, where there's simply no need to transpose a vector. If you do vectormatrix multiplication, it will multiply the vector in the way that works for the size of the matrix (unless it would have to change the order of the multiplication).